x^2+34x-25=0

Solution for x^2+34x-25=0 equation:

x^2+34x-25=0

a = 1; b = 34; c = -25;
Δ = b2-4ac
Δ = 342-4·1·(-25)
Δ = 1256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1256}=\sqrt{4*314}=\sqrt{4}*\sqrt{314}=2\sqrt{314}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(34)-2\sqrt{314}}{2*1}=\frac{-34-2\sqrt{314}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(34)+2\sqrt{314}}{2*1}=\frac{-34+2\sqrt{314}}{2}
$